/F3 17 0 R /Type /XObject /Matrix [1 0 0 1 0 0] BT /FormType 1 /Length 59 /F1 12.131 Tf /Meta255 Do endstream ET /Subtype /Form /FormType 1 q 1.007 0 0 1.007 271.012 450.181 cm /F3 17 0 R 6.746 5.203 TD stream /ProcSet[/PDF] (D) Tj /Matrix [1 0 0 1 0 0] stream 1.007 0 0 1.007 271.012 703.126 cm Q q 1.007 0 0 1.007 551.058 330.484 cm 1.007 0 0 1.007 551.058 277.035 cm q /F2 11 0 R >> >> Q 1.007 0 0 1.007 551.058 636.879 cm endstream ET endobj /Matrix [1 0 0 1 0 0] /Meta83 97 0 R 0 G q /Subtype /Form /ProcSet[/PDF/Text] stream q /Meta76 Do /F3 12.131 Tf q /Length 69 q /FormType 1 >> Q << >> Q /ProcSet[/PDF] >> /Type /XObject /F1 7 0 R 0 g /Length 16 13.464 5.203 TD /Length 54 /Matrix [1 0 0 1 0 0] /Meta204 218 0 R q /FontDescriptor 10 0 R 79 0 obj /Resources<< 0.425 Tc Q >> /Font << Q Q Q /Meta146 160 0 R endstream q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] endobj Q /Type /XObject /Length 54 q >> q q endobj 406 0 obj /Font << 1.014 0 0 1.007 111.416 636.879 cm /ProcSet[/PDF/Text] 0 g /Matrix [1 0 0 1 0 0] 1 g ET /Meta418 434 0 R q 1 i 0.737 w /Type /XObject 109 0 obj 0 g 0 G >> 0.297 Tc endstream Q /BBox [0 0 88.214 16.44] /Font << stream stream >> q /FormType 1 /Length 12 q /Font << 0 g Q /Resources<< Answered by Sneha shidid | 06 Jun, 2019, 05:07: PM ET /Meta336 350 0 R /F1 12.131 Tf >> stream 0 G /Length 106 /Type /XObject Q q Q [(Answe)20(r Key)] TJ Q /BBox [0 0 534.67 16.44] endobj S /Font << /F3 12.131 Tf >> 3.742 5.203 TD Q stream /Meta206 220 0 R >> 1.007 0 0 1.007 411.035 330.484 cm Q q << Q (+) Tj endstream >> /Type /XObject endobj 32.201 5.203 TD BT /F1 12.131 Tf >> /Length 59 /ProcSet[/PDF/Text] /Type /XObject stream 1 i Q Q /Resources<< 0 G 12.727 5.203 TD /BBox [0 0 17.177 16.44] Q Q /F3 17 0 R >> /Length 16 6.746 24.649 TD /Resources<< /Meta216 230 0 R Q 0 20.154 m /Subtype /Form >> /FormType 1 /Subtype /Form /Length 78 endobj >> /Meta265 279 0 R << q 1 i << endobj (x ) Tj BT /FormType 1 q >> << the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three . /Subtype /Form /Subtype /Form 0.564 G /Font << >> endstream Q 427 0 obj stream c Site 5 is not included in this number. /Matrix [1 0 0 1 0 0] Q q /Meta97 Do >> /BBox [0 0 88.214 16.44] /Meta212 Do Q /ProcSet[/PDF/Text] endobj /Subtype /Form q q /FormType 1 >> /Length 59 1 i /Matrix [1 0 0 1 0 0] endobj /Resources<< 1 i BT /Type /XObject (B\)) Tj /Resources<< Q /ProcSet[/PDF] q /Font << 0 w /BBox [0 0 88.214 35.886] Q Q /F3 17 0 R Q /Type /XObject /Meta165 179 0 R Q q >> BT 68 0 obj /Meta32 Do /Length 69 1.007 0 0 1.007 45.168 713.666 cm Q Thrice of a number = 3x. q /Type /XObject >> /Matrix [1 0 0 1 0 0] Q (\)]) Tj /Encoding /WinAnsiEncoding /F3 17 0 R 0.458 0 0 RG Q endstream /Resources<< /BBox [0 0 534.67 16.44] /Matrix [1 0 0 1 0 0] 1 i If we let "a number" be represented by the variable x, we can translate the given statement into an inequality as: 2x - 4 <= 26. >> answered 01/28/17, Mathematics - Algebra a Specialty / F.I.T. ET q Q 1.005 0 0 1.007 102.382 293.596 cm q /F3 17 0 R BT /Type /XObject Q q /Resources<< /Subtype /Form /Resources<< /Matrix [1 0 0 1 0 0] endobj Q Q << /FormType 1 /Matrix [1 0 0 1 0 0] /Length 118 1 i endobj Q >> q endstream 0 G /Meta4 13 0 R endstream endobj /Length 65 << Was this answer helpful? >> /F3 12.131 Tf q Q /Meta104 118 0 R /Length 69 Q ET /Length 59 /FormType 1 Q 500 500 500 0 333 389 278 0 0 722 500 500]>> /FormType 1 /BBox [0 0 30.642 16.44] 6.746 5.203 TD 0 g , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. << twice a number x added to 10 = 2x + 10. a number n decreased by five = n - 5. a number and multiplied by 7 = 7y. /BBox [0 0 15.59 16.44] stream Q 1 i 94 0 obj 1.007 0 0 1.007 411.035 636.879 cm 153 0 obj >> /Meta422 Do 2.238 5.203 TD /Meta253 267 0 R How many points did Kobe score in the season? endobj /Subtype /Form To find: The. endstream Q 1 i /Matrix [1 0 0 1 0 0] /Type /XObject /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] q Q q >> endobj >> /Font << /Font << /Meta109 Do endstream 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) 0.838 Tc Q 1.014 0 0 1.007 531.485 583.429 cm q << << BT 0 g /Matrix [1 0 0 1 0 0] /Length 16 /Meta46 Do BT 1 i q BT /ProcSet[/PDF/Text] 104 0 obj endobj Q Q /BBox [0 0 15.59 16.44] endobj q /ProcSet[/PDF/Text] /F4 12.131 Tf /Meta134 Do 59 0 obj /Font << /Resources<< endstream q /BBox [0 0 88.214 35.886] Q Q /Matrix [1 0 0 1 0 0] /Meta212 226 0 R /Meta21 32 0 R /Meta5 Do /Descent -299 q Q /FormType 1 (3\)) Tj /Subtype /Form 1.005 0 0 1.007 102.382 400.496 cm /Type /XObject stream Q endstream /Matrix [1 0 0 1 0 0] q >> /Font << /Meta55 Do /Meta169 Do q q >> >> << /F3 17 0 R 17.234 5.203 TD 2x - y = 6. Q /Meta346 360 0 R /Type /XObject Q endobj stream q 41.186 5.203 TD /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Subtype /Form endobj >> >> 1 i /Meta224 Do Q 0 w endobj Q 1 i Q Q q endobj 0 g 0 g /Subtype /Form /FormType 1 /Font << Q 1.014 0 0 1.007 251.439 450.181 cm 0 g 0 g >> 1 i endobj /Font << << /Meta71 85 0 R /Type /XObject /ProcSet[/PDF] /Subtype /Form >> Q q 2x - 15 = -27. stream /ProcSet[/PDF/Text] Q endobj << 0.296 Tc >> /Resources<< Q /Flags 32 /Type /XObject /Type /XObject 159 0 obj /Length 68 q >> /ProcSet[/PDF/Text] (C\)) Tj q ET 0 G >> /FormType 1 >> 1.007 0 0 1.007 551.058 383.934 cm 1.007 0 0 1.007 411.035 583.429 cm /BBox [0 0 88.214 16.44] >> /F1 12.131 Tf Q BT endstream /Length 16 Q /Meta419 Do 1 i Q >> Q 0 g 1 i 0 g 169 0 obj q Q /Meta28 41 0 R Q >> /Length 16 stream 0 w Q q << /FormType 1 endstream /Resources<< 0.737 w /Meta285 299 0 R 1.005 0 0 1.007 102.382 653.441 cm 1.005 0 0 1.007 102.382 799.486 cm q /Matrix [1 0 0 1 0 0] /Meta49 Do /ProcSet[/PDF/Text] 290 0 obj Q /FormType 1 >> /FormType 1 endstream /Resources<< ( x) Tj >> endstream Diabetes, also known as diabetes mellitus, is a group of common endocrine diseases characterized by sustained high blood sugar levels. >> q Q endstream /Length 16 Q 0 g BT /F3 12.131 Tf >> 0 G /FormType 1 1 i 1 i q /Length 118 /BBox [0 0 88.214 16.44] /Subtype /Form q q >> << Q 1 i q /F3 17 0 R /BBox [0 0 88.214 35.886] q /BBox [0 0 534.67 16.44] /BBox [0 0 534.67 16.44] stream 1 g Q stream 1 i /Resources<< /ProcSet[/PDF] endstream 0 G /F3 12.131 Tf Q ET 1.502 5.203 TD BT /Info 3 0 R >> /F3 12.131 Tf Q /Meta383 Do >> Q /BBox [0 0 17.177 16.44] /Length 69 16.469 5.336 TD /Meta292 Do /BBox [0 0 534.67 16.44] 1.007 0 0 1.006 130.989 690.329 cm 0.486 Tc /Type /XObject Q >> q Q >> /Length 69 0 g q /Flags 32 0.458 0 0 RG /Meta418 Do q endstream /FormType 1 /ProcSet[/PDF] /ProcSet[/PDF/Text] /F2 11 0 R >> q 0 G 1 i 0 20.154 m /Subtype /Form 1.502 24.649 TD 2x - y = 6. x + 3y = -25. >> /Meta276 290 0 R q /I0 51 0 R 0 G Q endstream endobj Q Q /Resources<< stream /Subtype /Form Q Q /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 0 g Q Q 23.216 5.203 TD /Meta48 Do stream Q /Meta203 217 0 R 437 0 obj Q /FormType 1 q stream /F3 17 0 R Q ET >> /Resources<< q /Font << Q >> /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Matrix [1 0 0 1 0 0] 1 i /Font << q /Parent 1 0 R /BBox [0 0 88.214 16.44] 403 0 obj /BaseFont /PalatinoLinotype-Bold /Matrix [1 0 0 1 0 0] /Length 58 Q >> >> /F3 17 0 R q /FormType 1 q endstream /Type /Pages /Meta380 Do q /BBox [0 0 88.214 16.44] 549.694 0 0 16.469 0 -0.0283 cm q 100 0 obj /ProcSet[/PDF/Text] q 0 w q q endobj /BBox [0 0 534.67 16.44] >> /FormType 1 0 w /XHeight 477 << q /BBox [0 0 15.59 16.44] /Type /XObject endobj /FormType 1 /ProcSet[/PDF/Text] Q /BBox [0 0 549.552 16.44] /FormType 1 stream /Meta193 207 0 R Q 2. 1 i /F3 12.131 Tf 1.502 24.339 TD 1.007 0 0 1.007 551.058 636.879 cm q /Type /XObject /Subtype /Form q Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. /FontBBox [-90 -216 1195 800] 1 i /Type /XObject /Type /XObject /ProcSet[/PDF] 1.502 5.203 TD >> /Type /XObject q 1 i ET 1 i /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] endobj 207 0 obj >> /F3 12.131 Tf 0 g 0.458 0 0 RG Q 20-n c.) n+20 d.) 20+n 3.) /Subtype /Form /BBox [0 0 30.642 16.44] /Length 78 32.201 5.203 TD q 0 g /F3 17 0 R /Meta344 358 0 R Q /Meta8 19 0 R Q Q q endstream 7 0 obj /Resources<< /Meta256 Do endstream << /I0 Do 1.014 0 0 1.007 391.462 849.172 cm So let's go ahead and identify a v /Resources<< /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] Q << q >> 214 0 obj /Type /XObject /Subtype /Form -0.099 Tw /FormType 1 Have a nice day! >> /Length 69 /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] endobj 0.269 Tc /Type /XObject 1 i /F3 12.131 Tf 0.458 0 0 RG 92 0 obj >> Q endstream /ProcSet[/PDF] stream /Font << /Ascent 891 q Q 0.486 Tc ET q >> q ET /Meta190 204 0 R Q /Type /XObject /ProcSet[/PDF/Text] << /BBox [0 0 88.214 16.44] endobj /BBox [0 0 534.67 16.44] << /Font << /Subtype /Form 0 g /F3 12.131 Tf 9.723 5.336 TD endstream /Resources<< Q /Filter [/CCITTFaxDecode] (C\)) Tj /F4 36 0 R q 1.007 0 0 1.007 411.035 583.429 cm endobj /Resources<< 0 g q stream 0 G /Resources<< q Q /Subtype /Form /Matrix [1 0 0 1 0 0] /Resources<< q 0 w >> Q >> stream /Type /XObject 1 i Q /ProcSet[/PDF] /FormType 1 Q /Resources<< stream endstream /ProcSet[/PDF] endstream /BBox [0 0 639.552 16.44] /Length 118 /F3 12.131 Tf q q Q /Font << >> 1.007 0 0 1.007 45.168 846.161 cm /Resources<< >> /Resources<< /FormType 1 Q BT 0 g << >> /Type /XObject /F3 12.131 Tf Q q /Type /XObject 0.737 w q q endstream q /Meta375 389 0 R q Negative thirteen decreased by 3 times a number x. /Meta288 302 0 R /Length 70 >> /Resources<< q endobj /FormType 1 q /Meta50 Do stream /Meta350 Do /Type /XObject >> /BBox [0 0 17.177 16.44] Q /Meta113 127 0 R q /Subtype /Form /FormType 1 /Length 104 endobj ET /Meta176 190 0 R >> /Matrix [1 0 0 1 0 0] /Meta215 Do Q << 20.21 5.203 TD q (5\)) Tj endobj >> /ProcSet[/PDF/Text] 2.238 5.203 TD endstream 0 g -0.486 Tw Q /ProcSet[/PDF/Text] 0 g 1.007 0 0 1.006 551.058 763.351 cm /Matrix [1 0 0 1 0 0] ET q 1 i ET /BBox [0 0 30.642 16.44] << 0 g /Subtype /Form BT stream 0 G Check out a sample Q&A here. >> endstream /FormType 1 endstream q >> q /Resources<< /BBox [0 0 17.177 16.44] BT 0 G 1.007 0 0 1.007 130.989 383.934 cm endobj /Font << 0 g 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . /Type /XObject Q 0 g << /Meta396 412 0 R 1.007 0 0 1.007 130.989 636.879 cm /FormType 1 Q 0 G /Type /XObject 56 0 obj 0.458 0 0 RG /Meta148 162 0 R Q ET >> /ProcSet[/PDF/Text] >> 0 G << 28 0 obj 0 G /F3 17 0 R 1 g Q >> /Subtype /Form 1 i ( \() Tj /ProcSet[/PDF/Text] 0 g 1.007 0 0 1.007 67.753 872.509 cm 0 5.203 TD endstream /FormType 1 /Meta177 191 0 R /Meta258 272 0 R >> 0.737 w 0 w >> 49 0 obj /FormType 1 /ProcSet[/PDF] >> endstream /Font << endstream BT 1.005 0 0 1.007 102.382 563.103 cm endstream q Q 0.564 G /Type /XObject stream << /FormType 1 Q /ProcSet[/PDF] 1 g Twice a number decreased by 8 gives 58. 0.486 Tc stream endstream q q 0 G endstream << Q /Length 118 145 0 obj /ProcSet[/PDF/Text] /BBox [0 0 30.642 16.44] endobj BT /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] endstream /Subtype /Form /Meta30 Do /Resources<< Q 0.458 0 0 RG /Resources<< stream /BBox [0 0 30.642 16.44] q 368 0 obj stream endstream 219 0 obj /FormType 1 q >> q /Type /FontDescriptor q Q (+) Tj /Subtype /Form 3.742 5.203 TD q /ProcSet[/PDF] endstream /F1 7 0 R endstream 0 g Q 0 G /Type /XObject << If a number is 50%, then it is a half - the same as 0.5 or 1/2. ET /Type /XObject >> 204 0 obj (\)) Tj 0.297 Tc 0 g 85 0 obj q endstream /Meta103 117 0 R /FormType 1 stream /ProcSet[/PDF/Text] Q 0 g 0 g ET q Two fewer than a number doubled is the same as the number decreased by 38. Q /Matrix [1 0 0 1 0 0] /FormType 1 five times the sum of a number x and two b.) /BBox [0 0 88.214 35.886] 32.201 5.203 TD /BBox [0 0 15.59 16.44] BT endstream /FormType 1 [( subt)-17(racted fr)-14(om a )-16(number)] TJ q S /ProcSet[/PDF/Text] Q /Matrix [1 0 0 1 0 0] 26.219 5.203 TD >> /BBox [0 0 30.642 16.44] /Subtype /Form stream q 1.007 0 0 1.007 551.058 330.484 cm q /BBox [0 0 15.59 16.44] q (D) Tj 0 g Solution: Let the number be x. endstream << /Subtype /Form q q /Subtype /Form << 0 w /Resources<< /Type /XObject 0 G ET /ProcSet[/PDF] /F3 17 0 R stream stream /BBox [0 0 15.59 16.44] /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] endstream /Contents [446 0 R] 0.369 Tc /BBox [0 0 88.214 16.44] q /Length 67 1 i q /Meta260 274 0 R Q 0 G /Matrix [1 0 0 1 0 0] endobj /ProcSet[/PDF] 0.737 w /Type /XObject q (5) Tj BT 0.458 0 0 RG /Resources<< The sum Of twice a nu4ber What is the number? Q >> q Q 0.458 0 0 RG 1.014 0 0 1.006 531.485 836.374 cm 65.906 4.894 TD /Type /XObject stream ET q 0 G BT /Subtype /Form /Matrix [1 0 0 1 0 0] /FormType 1 0.737 w 0.564 G /FormType 1 /BBox [0 0 30.642 16.44] 0 0 Similar questions Find the number which when decreased by 8% becomes 506. /Resources<< q endstream Q endstream 1 i >> q 1.005 0 0 1.007 102.382 473.519 cm q ET Q /FormType 1 0 G 1.007 0 0 1.007 67.753 726.464 cm ET /Matrix [1 0 0 1 0 0] /Font << BT >> Q /ProcSet[/PDF/Text] 1 i /BBox [0 0 673.937 68.796] Q Q /Meta155 169 0 R endobj endobj Q 0 g >> stream endstream 0 g /Type /XObject q Q q 1.005 0 0 1.015 45.168 53.449 cm >> /F3 17 0 R /Type /XObject 0 g /Type /XObject endobj q endstream 0.737 w q /MissingWidth 250 1.007 0 0 1.007 411.035 849.172 cm >> stream Q 38.948 5.203 TD /Subtype /Form 1 g BT /Subtype /Form << q >> All steps. q /Subtype /Form /BBox [0 0 549.552 16.44] Q stream /Resources<< 0.737 w Q >> /Subtype /Form q /Meta42 56 0 R q /Type /XObject /Subtype /Form /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] 9.723 5.336 TD 0 w /Meta346 Do /Type /XObject /BBox [0 0 88.214 35.886] /Font << Q /FormType 1 stream >> << endobj Q q /ProcSet[/PDF/Text] Q: when six times a number is decreased by 4, the result is 8. Q 0.737 w q >> /Type /XObject q >> /Matrix [1 0 0 1 0 0] q /F3 17 0 R 1 g >> >> /Meta214 Do /FormType 1 /FormType 1 /Length 16 stream /Resources<< /Font << Q 0.564 G 1.007 0 0 1.007 271.012 383.934 cm /Font << << 0 g << /Matrix [1 0 0 1 0 0] q 0.564 G Q Q 0 G /FormType 1 /Matrix [1 0 0 1 0 0] /Type /XObject >> Q /Matrix [1 0 0 1 0 0] Q endobj /Length 70 Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] stream ET endobj 1 i /BBox [0 0 549.552 16.44] /Meta261 Do q 231 0 obj q q 0 g q q Q q endstream /Subtype /Form 117 0 obj /F4 36 0 R 1.007 0 0 1.007 130.989 583.429 cm q /Resources<< You can specify conditions of storing and accessing cookies in your browser, Twice a number, decreased by 58 is less than 112, Mr. Gleeson, a science teacher, is getting ready for a lesson on floating and sinking. 0 g 0.458 0 0 RG 32.201 20.154 l 1 g << q 0 G ET BT >> stream S q endobj /Meta243 Do /FormType 1 /Subtype /Form /Meta77 91 0 R q /FormType 1 q /Type /XObject 549.694 0 0 16.469 0 -0.0283 cm 1 g 0.369 Tc -0.486 Tw Q /Length 69 Q /Length 70 >> /ProcSet[/PDF] /FormType 1 endstream endstream q 1.007 0 0 1.007 130.989 383.934 cm /Length 69 /Subtype /Form 1.007 0 0 1.007 411.035 849.172 cm 319 0 obj /Font << Q 0 g stream >> Q BT Q 0 g q (-) Tj /ProcSet[/PDF] /Resources<< 250 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 q stream Q << q 1.005 0 0 1.007 102.382 599.991 cm /Length 16 /Subtype /Form /Meta310 Do q /F3 12.131 Tf /BBox [0 0 88.214 16.44] /Meta85 Do 0 g q q q /Resources<< /ProcSet[/PDF/Text] /F3 17 0 R >> 129 0 obj So we have twice of a mystery number decreased by three, and that is all going to be 31. /BBox [0 0 534.67 16.44] /Length 79 /ProcSet[/PDF] 1 i /Resources<< Q Q [(-1)-16(52)] TJ Q endstream /Length 68 /Matrix [1 0 0 1 0 0] 0.737 w 0.369 Tc /Font << /FormType 1 19.474 5.203 TD q Q >> Q 0 g << /ProcSet[/PDF/Text] 1.005 0 0 1.007 102.382 400.496 cm endstream BT q (D\)) Tj /Font << /ProcSet[/PDF/Text] >> (-) Tj 0 G /Type /XObject >> >> q /Resources<< /Type /XObject q /Type /XObject /FormType 1 /F1 7 0 R /Subtype /Form endobj >> /FormType 1 Q stream Q /Length 16 /ProcSet[/PDF/Text] /Meta96 Do /FormType 1 Q 0 20.154 m >> endobj /Meta386 Do

Two Doors Down What Happened To Jazz, Justice Is Reason Enough Poem, Trpnutie Lavej Ruky A Nohy, Can I Use Canva Education For Commercial Use, Articles T